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Links to relevant publications on the WWW Procedure for determining the concentration of Sulphate (SO4-2) in WATER Although there is no electrode sensitive to the Sulphate ion this can be determined by reacting with an excess of Barium Chloride standard and precipitating as BaSO4. The amount of Barium removed from solution is monitored with a Barium electrode and is exactly equivalent to the amount of Sulphate in the sample solution. The result is calculated using the Standard Subtraction method.
Apparatus Required Ion-Selective Electrode for Barium ion (ELIT 8081 – PVC membrane) Reference electrode: single junction silver chloride (ELIT 001) Dual electrode head (ELIT 201 - with BNC connector) Standard solution: BaCl2 ELIT Computer Interface/Ion Analyser, or Ion/pH/mV meter. Calibration Before use, the electrodes must be calibrated to find an accurate value for the slope under the current operating conditions. This can done by measuring 1 mM/L and 0.1 mM/L Barium standard solutions and finding the difference between the two measured voltages. Normally the slope is expected to be about 26±3 mV per decade of concentration for divalent ions. Sample Measurement
Results The unknown sulphate concentration (in moles) can be calculated from the following equation: Cu = Cs x {(Vu + Vs) / Vu} x {(10^((E2-E1)/S))) - (Vs / (Vs + Vu))} Where: Cu and Vu are the concentration and volume of the unknown sulphate sample, Cs and Vs are the concentration and volume of the standard barium solution, E2-E1 is the change in electrode potential S is the electrode slope Interference The following ions cause interference to the Barium measurement (selectivity coefficients in brackets): Strontium (0.085), Potassium (0.015), Sodium (0.015), Magnesium (0.006), Ammonium (0.003), Calcium (0.002), Lithium (0.0016). Strontium has the highest interference but is
unlikely to be present in significant concentrations in most samples. Any
Potassium or Sodium ions present will cause a significant positive error
if they have concentrations of greater than ten times that of the Barium.
For example, 1 mM of K is equivalent to about 0.015 mM of Ba so, if K/Ba = 10 then the Ba result will be approximately 15% too high and hence the SO4 will be approx. 15% too low. Similarly, Magnesium can be tolerated up to about twenty times the Barium, and Calcium & Lithium up to about fifty times. |